切片重组（reslice）

我们已经知道切片创建的时候通常比相关数组小，例如：

slice1 := make([]type, start_length, capacity)

其中 start_length 作为切片初始长度而 capacity 作为相关数组的长度。

这么做的好处是我们的切片在达到容量上限后可以扩容。改变切片长度的过程称之为切片重组 reslicing，做法如下：slice1 = slice1[0:end]，其中 end 是新的末尾索引（即长度）。

将切片扩展 1 位可以这么做：

sl = sl[0:len(sl)+1]

切片可以反复扩展直到占据整个相关数组。

示例 7.11 reslicing.go

package main
import "fmt"

func main() {
    slice1 := make([]int, 0, 10)
    // load the slice, cap(slice1) is 10:
    for i := 0; i < cap(slice1); i++ {
        slice1 = slice1[0:i+1]
        slice1[i] = i
        fmt.Printf("The length of slice is %d\n", len(slice1))
    }

    // print the slice:
    for i := 0; i < len(slice1); i++ {
        fmt.Printf("Slice at %d is %d\n", i, slice1[i])
    }
}

输出结果：

The length of slice is 1
The length of slice is 2
The length of slice is 3
The length of slice is 4
The length of slice is 5
The length of slice is 6
The length of slice is 7
The length of slice is 8
The length of slice is 9
The length of slice is 10
Slice at 0 is 0
Slice at 1 is 1
Slice at 2 is 2
Slice at 3 is 3
Slice at 4 is 4
Slice at 5 is 5
Slice at 6 is 6
Slice at 7 is 7
Slice at 8 is 8
Slice at 9 is 9

另一个例子：

var ar = [10]int{0,1,2,3,4,5,6,7,8,9}
var a = ar[5:7] // reference to subarray {5,6} - len(a) is 2 and cap(a) is 5

将 a 重新分片：

a = a[0:4] // ref of subarray {5,6,7,8} - len(a) is now 4 but cap(a) is still 5

问题 7.7

1) 如果 a 是一个切片，那么 s[n:n] 的长度是多少？

2) s[n:n+1] 的长度又是多少？

链接

PreviousFor-range 结构 Next切片的复制与追加

Last updated 6 years ago